1/x-4+2/x^2-16=3/x+4

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Solution for 1/x-4+2/x^2-16=3/x+4 equation:



1/x-4+2/x^2-16=3/x+4
We move all terms to the left:
1/x-4+2/x^2-16-(3/x+4)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: x^2!=0
x^2!=0/
x^2!=√0
x!=0
x∈R
Domain of the equation: x+4)!=0
x∈R
We add all the numbers together, and all the variables
1/x+2/x^2-(3/x+4)-20=0
We get rid of parentheses
1/x+2/x^2-3/x-4-20=0
We calculate fractions
We do not support expression: x^3

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